0.3x^2-x-4=0

Solution for 0.3x^2-x-4=0 equation:

0.3x^2-x-4=0

We add all the numbers together, and all the variables

0.3x^2-1x-4=0

a = 0.3; b = -1; c = -4;
Δ = b2-4ac
Δ = -12-4·0.3·(-4)
Δ = 5.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{5.8}}{2*0.3}=\frac{1-\sqrt{5.8}}{0.6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{5.8}}{2*0.3}=\frac{1+\sqrt{5.8}}{0.6}
$